#!/usr/bin/env python """ Use PyCrypto to generate test data for Cryptech ModExp core. """ # Author: Rob Austein # Copyright (c) 2015, NORDUnet A/S # All rights reserved. # # Redistribution and use in source and binary forms, with or without # modification, are permitted provided that the following conditions are # met: # - Redistributions of source code must retain the above copyright notice, # this list of conditions and the following disclaimer. # # - Redistributions in binary form must reproduce the above copyright # notice, this list of conditions and the following disclaimer in the # documentation and/or other materials provided with the distribution. # # - Neither the name of the NORDUnet nor the names of its contributors may # be used to endorse or promote products derived from this software # without specific prior written permission. # # THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS "AS # IS" AND ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED # TO, THE IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A # PARTICULAR PURPOSE ARE DISCLAIMED. IN NO EVENT SHALL THE COPYRIGHT # HOLDER OR CONTRIBUTORS BE LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL, # SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT NOT LIMITED # TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF USE, DATA, OR # PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND ON ANY THEORY OF # LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT (INCLUDING # NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE OF THIS # SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE. from argparse import ArgumentParser, FileType from Crypto import __version__ as PyCryptoVersion from Crypto.PublicKey import RSA from Crypto.Hash import SHA256 from Crypto.Util.number import long_to_bytes, inverse from Crypto.Signature.PKCS1_v1_5 import EMSA_PKCS1_V1_5_ENCODE, PKCS115_SigScheme from textwrap import TextWrapper import sys, os.path def KeyLengthType(arg): val = int(arg) if val % 8 != 0: raise ValueError return val parser = ArgumentParser(description = __doc__) parser.add_argument("--pad-to-modulus", action = "store_true", help = "zero-pad to modulus size (bug workaround)") parser.add_argument("--extra-word", action = "store_true", help = "add extra word of zero padding (bug workaround)") parser.add_argument("-k", "--key-lengths", type = KeyLengthType, nargs = "*", default = [1024, 2048, 4096], help = "Lengths in bits of keys to generate") parser.add_argument("--pkcs-encoding", type = int, choices = (1, 8), default = 8, help = "PKCS encoding to use for PEM commented private key") parser.add_argument("output", nargs = "?", type = FileType("w"), default = sys.stdout, help = "output file") args = parser.parse_args() plaintext = "You can hack anything you want with TECO and DDT." scriptname = os.path.basename(sys.argv[0]) wrapper = TextWrapper(width = 78, initial_indent = " " * 2, subsequent_indent = " " * 2) def printlines(*lines, **kwargs): for line in lines: args.output.write(line % kwargs + "\n") def trailing_comma(item, sequence): return "" if item == sequence[-1] else "," def print_hex(name, value, comment): printlines("static const uint8_t %(name)s[] = { /* %(comment)s, %(length)d bytes */", wrapper.fill(", ".join("0x%02x" % ord(v) for v in value)), "};", "", name = name, comment = comment, length = len(value)) def pad_to_blocksize(value, blocksize): extra = len(value) % blocksize return value if extra == 0 else ("\x00" * (blocksize - extra)) + value # Funnily enough, PyCrypto and Cryptlib use exactly the same names for # RSA key components, see Cryptlib documentation pages 186-187 & 339. h = SHA256.new(plaintext) printlines("/*", " * RSA signature test data for Cryptech project, automatically generated by", " * %(scriptname)s using PyCrypto version %(version)s. Do not edit.", " *", " * Plaintext: \"%(plaintext)s\"", " * SHA-256: %(digest)s", " */", "", scriptname = scriptname, version = PyCryptoVersion, plaintext = plaintext, digest = h.hexdigest()) fields = ("n", "e", "d", "p", "q", "dP", "dQ", "u", "m", "s") for k_len in args.key_lengths: k = RSA.generate(k_len) # Cryptlib insists u < p, probably with good reason, while k.u >= k.p: # and I'm sure not going to argue the math with Peter, k = RSA.generate(k_len) # so keep trying until we pass this test m = EMSA_PKCS1_V1_5_ENCODE(h, k_len/8) s = PKCS115_SigScheme(k).sign(h) assert len(m) == len(s) if args.pad_to_modulus: blocksize = k_len/8 if args.extra_word: blocksize += 4 else: blocksize = 4 printlines("/* %(k_len)d-bit RSA private key (PKCS #%(pkcs)d)", k.exportKey(format = "PEM", pkcs = args.pkcs_encoding), "*/", "", k_len = k_len, pkcs = args.pkcs_encoding) # PyCrypto doesn't precalculate dP or dQ, and for some reason it # does u backwards (uses (1/p % q) and swaps the roles of p and q in # the CRT calculation to compensate), so we just calculate our own. for name in fields: if name in "ms": continue elif name == "dP": value = k.d % (k.p - 1) elif name == "dQ": value = k.d % (k.q - 1) elif name == "u": value = inverse(k.q, k.p) else: value = getattr(k, name) print_hex("%s_%d" % (name, k_len), long_to_bytes(value, blocksize = blocksize), "key component %s" % name) print_hex("m_%d" % k_len, pad_to_blocksize(m, blocksize), "message to be signed") print_hex("s_%d" % k_len, pad_to_blocksize(s, blocksize), "signed message") printlines("typedef struct { const uint8_t *val; size_t len; } rsa_tc_bn_t;", "typedef struct { size_t size; rsa_tc_bn_t %(fields)s; } rsa_tc_t;", "", "static const rsa_tc_t rsa_tc[] = {", fields = ", ".join(fields)) for k_len in args.key_lengths: printlines(" { %(k_len)d,", k_len = k_len) for field in fields: printlines(" { %(field)s_%(k_len)d, sizeof(%(field)s_%(k_len)d) }%(comma)s", field = field, k_len = k_len, comma = trailing_comma(field, fields)) printlines(" }%(comma)s", comma = trailing_comma(k_len, args.key_lengths)) printlines("};") href='#n120'>120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 153 154 155 156 157 158 159 160 161 162 163 164 165 166 167 168 169 170 171 172 173 174 175 176 177 178 179 180 181 182 183 184 185 186 187 188 189 190 191 192 193 194 195 196 197 198 199 200 201 202 203 204 205 206 207 208 209 210 211 212 213 214 215 216 217 218 219 220 221 222 223 224 225 226 227 228 229 230 231 232 233 234 235 236 237 238 239 240 241 242 243 244 245 246 247 248 249 250 251 252 253 254 255 256 257 258